Integrand size = 38, antiderivative size = 35 \[ \int \frac {\operatorname {PolyLog}\left (2,1+\frac {b c-a d}{d (a+b x)}\right )}{(a+b x) (c+d x)} \, dx=-\frac {\operatorname {PolyLog}\left (3,1+\frac {b c-a d}{d (a+b x)}\right )}{b c-a d} \]
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Time = 0.05 (sec) , antiderivative size = 35, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.026, Rules used = {6745} \[ \int \frac {\operatorname {PolyLog}\left (2,1+\frac {b c-a d}{d (a+b x)}\right )}{(a+b x) (c+d x)} \, dx=-\frac {\operatorname {PolyLog}\left (3,\frac {b c-a d}{d (a+b x)}+1\right )}{b c-a d} \]
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Rule 6745
Rubi steps \begin{align*} \text {integral}& = -\frac {\text {Li}_3\left (1+\frac {b c-a d}{d (a+b x)}\right )}{b c-a d} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 30, normalized size of antiderivative = 0.86 \[ \int \frac {\operatorname {PolyLog}\left (2,1+\frac {b c-a d}{d (a+b x)}\right )}{(a+b x) (c+d x)} \, dx=\frac {\operatorname {PolyLog}\left (3,\frac {b (c+d x)}{d (a+b x)}\right )}{-b c+a d} \]
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Time = 8.38 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.03
method | result | size |
derivativedivides | \(\frac {\operatorname {Li}_{3}\left (1-\frac {a d -c b}{d \left (b x +a \right )}\right )}{a d -c b}\) | \(36\) |
default | \(\frac {\operatorname {Li}_{3}\left (1-\frac {a d -c b}{d \left (b x +a \right )}\right )}{a d -c b}\) | \(36\) |
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\[ \int \frac {\operatorname {PolyLog}\left (2,1+\frac {b c-a d}{d (a+b x)}\right )}{(a+b x) (c+d x)} \, dx=\int { \frac {{\rm Li}_2\left (\frac {b c - a d}{{\left (b x + a\right )} d} + 1\right )}{{\left (b x + a\right )} {\left (d x + c\right )}} \,d x } \]
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Timed out. \[ \int \frac {\operatorname {PolyLog}\left (2,1+\frac {b c-a d}{d (a+b x)}\right )}{(a+b x) (c+d x)} \, dx=\text {Timed out} \]
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\[ \int \frac {\operatorname {PolyLog}\left (2,1+\frac {b c-a d}{d (a+b x)}\right )}{(a+b x) (c+d x)} \, dx=\int { \frac {{\rm Li}_2\left (\frac {b c - a d}{{\left (b x + a\right )} d} + 1\right )}{{\left (b x + a\right )} {\left (d x + c\right )}} \,d x } \]
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\[ \int \frac {\operatorname {PolyLog}\left (2,1+\frac {b c-a d}{d (a+b x)}\right )}{(a+b x) (c+d x)} \, dx=\int { \frac {{\rm Li}_2\left (\frac {b c - a d}{{\left (b x + a\right )} d} + 1\right )}{{\left (b x + a\right )} {\left (d x + c\right )}} \,d x } \]
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Timed out. \[ \int \frac {\operatorname {PolyLog}\left (2,1+\frac {b c-a d}{d (a+b x)}\right )}{(a+b x) (c+d x)} \, dx=\int \frac {\mathrm {polylog}\left (2,1-\frac {a\,d-b\,c}{d\,\left (a+b\,x\right )}\right )}{\left (a+b\,x\right )\,\left (c+d\,x\right )} \,d x \]
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